Answer:
The answer to your question is letter a. 65.13%
Explanation:
Percent composition of Copper in Cu(OH)₂
Process
1.- Calculate the molecular weight of Copper hydroxide
Cu(OH)₂ = 64 + (16 x 2) + (2 x 1)
= 64 + 32 + 2
= 98 g
2.- Solve the problem using proportions
98 g of Cu(OH)₂ --------------- 100 %
64 g of Cu ---------------- x
x = (64 x 100) / 98
x = 6400 / 98
x = 65.2 %