Explanation:
The given data is as follows.
Flow of chlorine (Q) = [tex]10,000 m^{3}/day[/tex]
Amount of liter present per day is as follows.
[tex]10,000 \times 10^{3} l/day[/tex]
It is given that dosage of chlorine will be as follows.
10 mg/l = [tex]10 \times 10^{-6}[/tex] kg/l
Therefore, total chlorine requirement is as follows.
Total chlorine requirement = [tex](10,000 \times 10^{3}) \times (10 \times 10^{-6})[/tex] kg/day
= 100 kg/day
Thus, we can conclude that the kilograms of chlorine used daily at the given water treatment plant is 100 kg/day.
