how do I solve these three

Answer:
below
Step-by-step explanation:
2(x+5)=3x+1
2x+10=3x+1
10-1=3x-2x
9=x
x=9
3y-4=6-2y
3y+2y=6+4
5y=10
y=10/5
y=2
3(n+2)= 9(6-n)
3n+6=54-9n
3n+9n=54-6
12n=48
n=48/12
n=4
Answer:
Step-by-step explanation:
1) 2(x + 5) = 3x + 1
Multiplying each term inside the parenthesis by 2, it becomes
2x + 10 = 3x + 1
Subtracting 2x and - 1 from both sides of the equation
2x - 2x + 10 - 1 = 3x - 2x + 1 - 1
3x - 2x = 10 - 1
x = 9
2) 3y - 4 = 6 - 2y
Adding 4 and 2y to the left hand side and the right hand side of the equation, it becomes
3y + 2y - 4 + 4 = 6 + 4 + 2y - 2y
5y = 10
Dividing the both sides of the equation by 5, it becomes
5y/5 = 10/5
y = 10/2 = 5
3) 3(n + 2) = 9(6 - n)
3n + 6 = 54 - 9n
Subtracting 6 from both sides and adding 9n to both sides of the equation, it becomes
3n + 9n + 6 - 6 = 54 - 6 - 9n + 9n
12n = 48
Dividing both sides of the equation by 12, it becomes
12n/12 = 48/12
n = 4