Answer:
The coordinate to the given equations is (3,1)
Step-by-step explanation:
Given equation is [tex]2x+6y=12\hfill (1)[/tex]
and [tex]4x-3y=9\hfill (2)[/tex]
To find the coordinate of the given equations :
Multiply the equation (2) into 2 we get
[tex]8x-6y=18\hfill (3)[/tex]
Now adding the equations (1) and (3) we get
[tex]2x+6y=12[/tex]
[tex]8x-6y=18[/tex]
_______________
[tex]10x=30[/tex]
[tex]x=\frac{30}{10}[/tex]
Therefore x=3
Substitute x=3 in (1)
2(3)+6y=12
6y=12-6
[tex]y=\frac{6}{6}[/tex]
Therefore y=1
The coordinate to the given equations is (3,1)
