Answer:
Therefore the probability that in one turn James could roll an odd number and fip a heads on the quarter is = [tex]\frac{1}{2}[/tex] × [tex]\frac{1}{2}[/tex] = [tex]\frac{1}{4}[/tex].
Step-by-step explanation:
i) There are three odd numbered faces on the cube, that is the faces having 1, 3, and 5.
Therefore the probability of rolling an odd numbered face is = [tex]\frac{1}{6} + \frac{1}{6} + \frac{1}{6} = \frac{1}{2}[/tex] since the probability of rolling 1 = probability of rolling 3 = probability of rolling 5 = [tex]\frac{1}{6}[/tex]
ii) The probability of flipping a head on the quarter = probability of flipping a tail on the quarter = [tex]\frac{1}{2}[/tex]
iii) Therefore the probability that in one turn James could roll an odd number and fip a heads on the quarter is = [tex]\frac{1}{2}[/tex] × [tex]\frac{1}{2}[/tex] = [tex]\frac{1}{4}[/tex]