Answer:
1.29649
488.08706 nm
[tex]6.14644\times 10^{14}\ Hz[/tex]
231715700.28346 m/s
Explanation:
n denotes refractive index
1 denotes air
2 denotes solution
[tex]\lambda_0[/tex] = 632.8 nm
From Snell's law we have the relation
[tex]n_1sin\theta_1=n_2sin\theta_2\\\Rightarrow n_2=\dfrac{n_1sin\theta_1}{sin\theta_2}\\\Rightarrow n_2=\dfrac{1\times sin33}{sin24.84}\\\Rightarrow n_2=1.29649[/tex]
Refractive index of the solution is 1.29649
Wavelength is given by
[tex]\lambda=\dfrac{\lambda_0}{n_2}\\\Rightarrow \lambda=\dfrac{632.8}{1.29649}\\\Rightarrow \lambda=488.08706\ nm[/tex]
The wavelength of the solution is 488.08706 nm
Frequency is given by
[tex]f=\dfrac{c}{\lambda}\\\Rightarrow f=\dfrac{3\times 10^8}{488.08706\times 10^{-9}}\\\Rightarrow f=6.14644\times 10^{14}\ Hz[/tex]
The frequency is [tex]6.14644\times 10^{14}\ Hz[/tex]
[tex]v=\dfrac{c}{n_2}\\\Rightarrow v=\dfrac{3\times 10^8}{1.29469}\\\Rightarrow v=231715700.28346\ m/s[/tex]
The speed in the solution is 231715700.28346 m/s
