Respuesta :
Using the formula
P₁V₁ = P₂V₂ (where P is percentage and V is volume in pounds)
∴ [tex] (\frac{15}{100}) * (20) = ( \frac{12}{100}) * (x)[/tex] (where x is the unknown volume being found)
[tex] \frac{15}{100} * 20 * \frac{100}{12} = x[/tex]
x = 25
∴ In order for only 12 % of salt to be percent you need to have 25 pounds of water but since you already have 20 pounds of water and 15 % salt, you only need to find how much more pounds of water to add which is 5 (25 - 20 = 5)
P₁V₁ = P₂V₂ (where P is percentage and V is volume in pounds)
∴ [tex] (\frac{15}{100}) * (20) = ( \frac{12}{100}) * (x)[/tex] (where x is the unknown volume being found)
[tex] \frac{15}{100} * 20 * \frac{100}{12} = x[/tex]
x = 25
∴ In order for only 12 % of salt to be percent you need to have 25 pounds of water but since you already have 20 pounds of water and 15 % salt, you only need to find how much more pounds of water to add which is 5 (25 - 20 = 5)
5 pounds of water must be added.
What is Boyle's law?
The volume of a gas at constant temperature varies inversely with the pressure exerted on it.
Using Boyle's law
P1V1= P2V2
15/100* 20 = 12/100* V2
300= 12* V2
V2= 300/12
V2 =25
But since there is already 20 pounds of water and 15 % salt
So, only 5 pounds needed more.
Learn more about this concept here:
https://brainly.com/question/84262
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