Respuesta :
Based on the conditions given above, the number of bacteria at any time t (in hours) is calculated by the equation,
at = (a1)(2^t/2)
where a1 is the initial number of bacteria and at is the number at any time t. Substituting the givens,
a6 = (103)(2^6/2) = 824
Thus, there are 824 bacteria after 6 hours.
at = (a1)(2^t/2)
where a1 is the initial number of bacteria and at is the number at any time t. Substituting the givens,
a6 = (103)(2^6/2) = 824
Thus, there are 824 bacteria after 6 hours.
Formula for growth or decay
R= [tex]R_{0}[1 \pm \frac{r}{100}]^t[/tex]
R= Final population of Bacteria
[tex]R_{0}[/tex]= Initial Population
r = Rate of growth or decay
t= Time period
[tex]R_{0}[/tex]= 103 bacteria
when, t=2
R becomes 103 × 2= 206 bacteria
Substituting these values in the formula of growth
206 = 103 × [tex](1+ \frac{r}{100})^2[/tex]
Dividing both sides by 103, we get
2 = [tex](1+ \frac{r}{100})^2[/tex]
[tex](1+ \frac{r}{100})[/tex]= √2------(1)
[tex](1+ \frac{r}{100})[/tex]= 1.414
r = (1.414 -1) × 100= .414 × 100= 41.4%
Number of bacteria at the end of 6 hours = 103 × [tex](1+ \frac{r}{100})^6[/tex]= 103 × [tex][\sqrt{2}]^6[/tex] ------Using (1)
= 103 × 2³
=103 × 8
= 824→→bacteria that Harriet have in the dish at the end of 6 hours