A chemistry student needs of -bromobutane for an experiment. He has available of a w/w solution of -bromobutane in ethanol. Calculate the mass of solution the student should use. If there's not enough solution, press the "No solution" button. Round your answer to significant digits.

A chemistry student needs 15.00 g of 2-bromobutane for an experiment. He has available 220. g of a 30.0 % w/w solution of 2-bromobutane in ethanol. Calculate the mass of solution the student should use. If there's not enough solution, press the "No solution" button. Round your answer to 3 significant digits.

Answer: The mass of solution, the student should use is 50.0 grams

Explanation:

We are given:

30.0 % (w/w) of 2-bromobutane

This means that 30 grams of 2-bromobutane is present in 100 g of solution

Mass of solution given = 220. g

Mass of 2-bromobutane, the student needs = 15.00 g

Calculating the mass of 2-bromobutane in given amount of solution:

[tex]\Rightarrow 220\times \frac{30}{100}=66g[/tex]

To calculate the mass of solution, we use unitary method:

If 66 grams of 2-bromobutane is present in 220 grams of solution

So, 15 grams of 2-bromonutane will be present in [tex]\frac{220}{66}\times 15=50.0g[/tex] of solution

Hence, the mass of solution, the student should use is 50.0 grams