Respuesta :
Answer:
Apparent Specific Gravity = 2.88
bulk specific gravity = 2.76
Bulk Specific Gravity SSD = 2.80
absorption = 1.44%
bulk volume = 373.3
Explanation:
given data
oven dry weight A = 1034.0 g
moisture content = 4.0 %
saturated surface dry weight B = 1048.9 g
weight of the aggregate in water C = 675.6 g
solution
we get here Apparent Specific Gravity that is express as
Apparent Specific Gravity = [tex]\frac{A}{A-C}[/tex] ..........1
put here value
Apparent Specific Gravity = [tex]\frac{1034}{1034-675.6}[/tex]
Apparent Specific Gravity = 2.88
and
now we get bulk specific gravity that is
bulk specific gravity = [tex]\frac{A}{B-C}[/tex] ...................2
put here value
bulk specific gravity = [tex]\frac{1034}{1048.9-675.6}[/tex]
bulk specific gravity = 2.76
and
now we get Bulk Specific Gravity SSD
Bulk Specific Gravity SSD = [tex]\frac{B}{B-C}[/tex] ............3
Bulk Specific Gravity SSD = [tex]\frac{1048.9}{1048.9-675.6}[/tex]
Bulk Specific Gravity SSD = 2.80
and
now absorption will be here as
absorption = [tex]\frac{B-A}{A}[/tex] × 100% ................4
absorption = [tex]\frac{1048.9-1034}{1034}[/tex] × 100%
absorption = 1.44%
and
last we get bulk volume that is
bulk volume = [tex]\frac{weight\ displce\ water}{density\ water }[/tex]
bulk volume = [tex]\frac{1048.9-675.6}{1}[/tex]
bulk volume = 373.3
