Answer: 13%
Explanation:
The theoretical value for the density of vanadium is 6.11 g/cm3 while the experimental value determined in the laboratory is 6.9 g/cm3. To calculate the percentage error, the following formula is used
[tex]percentage error = ((|experimental value – theoretical value|)/theoretical value) *100[/tex]
[tex]percentage error = ((6.9-6.11)/6.11) * 100[/tex]
= 13%
The determined value for the density of vanadium has been 13 %. Thus, option C is correct.
The percent error has been given as the difference in the experimental value with respect to the theoretical value.
The percent error, (% Error) has been given by:
[tex]\%\;Error=\dfrac{E-T}{T}\;\times\;100[/tex]
Where, the theoretical value has been given by T.
The experimental value of the sample has been E.
For the density of vanadium sample,
[tex]E=6.9\;\rm g/cm^3\\\textit T=6.11\;g/cm^3[/tex]
Substituting the values for the percent error in the density of Vanadium:
[tex]\%\;Error=\dfrac{6.9-6.11}{6.11}\;\times\;100\\\%\;Error=\dfrac{0.79}{6.11}\;\times\;100\\\%\;Error=13\;\%[/tex]
The percent error in the determined value for the density of vanadium has been 13 %. Thus, option C is correct.
For more information about percent error, refer to the link:
https://brainly.com/question/3105259
