Respuesta :
Answer:
f = 2 f₀
Explanation:
A mass-spring system has angular velocity
w = √ k / m
The angular velocity is related to the frequency
w = 2π f
f = 1 /2π √k / m
If we change the mass for another that is ¼ of the initial mass
m = ¼ mo
We replace
f = 1 / 2π √(k 4 / mo)
f = (1 / 2π √k/m₀) √ 4
f = 2 f₀
In summary the frequency doubles from the initial frequency
The frequency of oscillation of the system by a factor of should be considered as the f = 2 f₀.
Frequency of oscillation:
Since
A mass-spring system has angular velocity that applied the following equation
w = √ k / m
Also,
The angular velocity should be related to the frequency
w = 2π f
f = 1 /2π √k / m
Now
In the case when we change the mass for another that is ¼ of the initial mass
So,
m = ¼ mo
Now
f = 1 / 2π √(k 4 / mo)
f = (1 / 2π √k/m₀) √ 4
f = 2 f₀
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