francine2210 francine2210

23-01-2020
Chemistry

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How many milliliters of 10.0 M HCl ( aq ) are needed to prepare 790.0 mL of 1.00 M HCl ( aq )

Respuesta :

dsdrajlin dsdrajlin

24-01-2020

Answer:

79.0 mL

Explanation:

Given data

Initial concentration (C₁): 10.0 M

Initial volume (V₁): ?

Final concentration (C₂): 1.00 M

Final volume (V₂): 790.0 mL

In order to find the volume required of the concentrated solution, we will use the dilution rule.

C₁ × V₁ = C₂ × V₂

V₁ = C₂ × V₂/C₁

V₁ = 1.00 M × 790.0 mL/10.0 M

V₁ = 79.0 mL

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