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A parking lot with an area of 9600 ft? (see diagram below) has a 200 ft fence built along
two adjacent sides of lengths 2 and y. If you were asked to find the dimensions of the
parking lot, what equations would you use for the perimeter and area of the parking lot?

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nandhini123

Answer:

x+y=200

xy=9,600

Step-by-step explanation:

The diagram shows rectangular parking lot with sides of x feet and y feet.

1. The area of the rectangle is  given by

A=Length \times Width

A = xy -------------------------(1)

We are given that the area of the parking lot is 9,600\ ft^2, then

eq(1) becomes

9,600  = xy ---------------------(2)

2. A parking lot has  a 200ft fence built along two adjacent sides of lengths x and y, then

Then the perimeter of the two adjacent sides

x+y=200 ---------------------------------(3)

Thus ,The system of two equations are

x+y=200

xy=9,600

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