Respuesta :
Answer:
0.435 M
Explanation:
In case of dilution , the following formula can be used -
M₁V₁ = M₂V₂
where ,
M₁ = initial concentration ,
V₁ = initial volume ,
M₂ = final concentration , i.e. , concentration after dilution ,
V₂ = final volume .
from , the question ,
M₁ = 0.725 M
V₁ = 300 mL
M₂ = ?
V₂ = 300 mL + 200 mL = 500 mL
Since, the final volume of solution would be the summation of the initial and final volume.
Using the above formula , the molarity of the final solution after dilution , can be calculated as ,
M₁V₁ = M₂V₂
0.725 M * 300 mL = M₂ * 500mL
M₂ = 0.435 M
The concentration of potassium ions in the final solution is 0.435 M.
Dilution calculations can be performed using the formula
M₁V₁ = M₂V₂
where ,
M₁ = initial concentration ,
V₁ = initial volume ,
M₂ = final concentration ,
V₂ = final volume
Given:
M₁ = 0.725 M
V₁ = 300 mL
M₂ = ?
V₂ = 300 mL + 200 mL = 500 mL
Since, the final volume of solution would be the total of initial and final volume.
Using the above formula , the molarity of the final solution after dilution , can be calculated as ,
[tex]M_1V_1 = M_2V_2\\\\0.725 M * 300 mL = M_2 * 500mL\\\\M_2 = 0.435 M[/tex]
The concentration of potassium ions in the final solution is 0.435 M.
Learn more about dilution here:
https://brainly.com/question/3203632
