Answer:
[tex]KE_2=3.24 \times KE_1[/tex]
Explanation:
given,
Speed of car = v
new speed of car v'= 1.8 v
Kinetic energy of the car
[tex]KE_1 =\dfrac{1}{2}mv^2[/tex]
new Kinetic energy of energy
[tex]KE_2 =\dfrac{1}{2}mv'^2[/tex]
[tex]KE_2=\dfrac{1}{2}m(1.8v)^2[/tex]
[tex]KE_2=3.24 \times \dfrac{1}{2}mv^2[/tex]
[tex]KE_2=3.24 \times KE_1[/tex]
hence, the kinetic energy is increased by the factor of 3.24.
