[tex]\frac{1}{5}(3x+\frac{1}{2} )=\frac{3x}{5}+\frac{1}{10}[/tex]
Solution:
Given expression is [tex]\frac{1}{5}(3x+\frac{1}{2} )[/tex].
Let us find the expanded form of the given expression.
To expand this multiply [tex]\frac{1}{5}[/tex] with each term inside the bracket.
[tex]\frac{1}{5}(3x+\frac{1}{2} )=\frac{1}{5}\times3x+\frac{1}{5}\times\frac{1}{2}[/tex]
[tex]=\frac{3x}{5}+\frac{1}{10}[/tex]
[tex]\frac{1}{5}(3x+\frac{1}{2} )=\frac{3x}{5}+\frac{1}{10}[/tex]
Hence the expanded form of the given expression is [tex]\frac{3x}{5}+\frac{1}{10}[/tex].