The average value of a certain type of automobile was 14,220 in 1993 and depreciated to 9,780 in 1997.
Let y be the average value of the automobile in the year x, where x=0 represents 1993. Write and graph a linear equation that models the value of the automobile in terms of the year x.

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24-01-2020
Mathematics

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The average value of a certain type of automobile was 14,220 in 1993 and depreciated to 9,780 in 1997.
Let y be the average value of the automobile in the year x, where x=0 represents 1993. Write and graph a linear equation that models the value of the automobile in terms of the year x.

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Ashraf82 Ashraf82 · Answer 1 · 2020-01-30T11:36:55+01:00

The linear equation that models the value of the automobile in terms of the year x is y = -1,110 x + 14,220

Step-by-step explanation:

The average value of a certain type of automobile was 14,220 in 1993 and depreciated to 9,780 in 1997

y be the average value of the automobile in the year x
x = 0 represents 1993

We need to write and graph a linear equation that models the value of the automobile in terms of the year x

The form of the linear equation is y = mx + b, where b is the initial value (value y at x = 0), and m is the rate of change

∵ The average value the of automobile was 14,220 in 1993

∵ x = 0 represents 1993

∴ The point which represent the data is (0 , 14,220)

- b is the value of y at x = 0

∴ b = 14,220

∵ The average automobile was 9,780 in 1997

- To find x subtract 1993 from 1997

∵ 1997 - 1993 = 4

∴ x = 4

∴ The point which represent the data is (4 , 9,780)

∵ m = Δy/Δx

∴ [tex]m=\frac{9780-14220}{4-0}[/tex]

∴ m = -1,110

- Substitute the values of m and b in the form of the equation

∴ y = -1,110 x + 14,220

The linear equation that models the value of the automobile in terms of the year x is y = -1,110 x + 14,220

The graph is attached below

Each square unit represents 1000 in the graph

Learn more:

You can learn more about the linear function in brainly.com/question/1284310

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MrRoyal MrRoyal · Answer 2 · 2022-01-18T11:37:41+01:00

A linear function is a function that changes at a constant rate.

The equation of the linear function is [tex]y = -1110x + 14220[/tex]

The given parameters are:

x = 0, y = 14220 ---- in 1993
x = 4, y = 9780 ---- in 1997

Start by calculating the slope (m)

[tex]m = \frac{y_2 - y_1}{x_2 - x_1}[/tex]

This gives

[tex]m = \frac{9780 - 14220}{4- 0}[/tex]

Simplify

[tex]m = \frac{-4440}{4}[/tex]

This gives

[tex]m = -1110[/tex]

The equation is then calculated as:

[tex]y = m(x -x_1) + y_1[/tex]

This gives

[tex]y = -1110(x -0) + 14220[/tex]

Expand

[tex]y = -1110x + 14220[/tex]

Hence, the equation of the linear relationship is [tex]y = -1110x + 14220[/tex]

See attachment for the graph

Read more about linear equations at:

https://brainly.com/question/14323743

The average value of a certain type of automobile was 14,220 in 1993 and depreciated to 9,780 in 1997.Let y be the average value of the automobile in the year x, where x=0 represents 1993. Write and graph a linear equation that models the value of the automobile in terms of the year x.

Respuesta :

Otras preguntas

The average value of a certain type of automobile was 14,220 in 1993 and depreciated to 9,780 in 1997.
Let y be the average value of the automobile in the year x, where x=0 represents 1993. Write and graph a linear equation that models the value of the automobile in terms of the year x.