Answer:
[tex]x=17[/tex]
Step-by-step explanation:
[tex]2x+3y=1[/tex]
[tex]y=-2-9[/tex]
- In order to combine these two equations, an idea you need to keep in mind is finding a way of setting these equations as equal to each other. I saw that each equation shared a common value, [tex]y[/tex]. In this case, we need to isolate [tex]y[/tex] in the first equation so that both equations [tex]=y[/tex].
[tex]2x+3y=1[/tex]
[tex]3y=-2x+1[/tex]
[tex]\frac{3y}{3}=\frac{-2x+1}{3}[/tex]
[tex]y=-\frac{2}{3}x+\frac{1}{3}[/tex]
- With this, we now know that both [tex]-2-9[/tex] and [tex]-\frac{2}{3}x+\frac{1}{3}[/tex] are equal to [tex]y[/tex], so we can set them equal to each other.
[tex]y=-\frac{2}{3}x+\frac{1}{3}[/tex]
[tex]y=-11[/tex]
[tex]-\frac{2}{3}x+\frac{1}{3}=-11[/tex]
- Reply to this if anything I'm saying or doing is confusing in any way, or if you find a mistake. :) Solve for [tex]x[/tex].
[tex]-\frac{2}{3}x+\frac{1}{3}=-11[/tex]
[tex]-\frac{2}{3}x=-11-\frac{1}{3}[/tex]
[tex]-\frac{2}{3}x =-\frac{33}{3}-\frac{1}{3}[/tex]
[tex]-\frac{2}{3}x =-\frac{34}{3}[/tex]
[tex]-\frac{2}{3}x(-\frac{3}{2})=-\frac{34}{3}(-\frac{3}{2})[/tex]
[tex]x=\frac{102}{6}=17[/tex]
[tex]x=17[/tex]
- Hopefully this answer is correct AND makes sense in terms of how I achieved it. Again, reply to this with any questions or mistakes I made and I'll do my best to answer or fix them.
