The strength of the magnetic field is 0.089 T
Explanation:
The force caused by a magnetic field on a current-carrying wire is given by the equation
[tex]F=ILB sin \theta[/tex]
where
I is the current in the wire
L is the length of the wire
B is the strength of the magnetic field
[tex]\theta[/tex] is the angle between the direction of the field and the wire
In this problem, we have
L = 0.57 m
I = 9.7 A
F = 0.49 N
[tex]\theta=90^{\circ}[/tex] since the wire is perpendicular to the field
Solving for B, we find the strength of the field:
[tex]B=\frac{F}{ILsin \theta}=\frac{0.49}{(9.7)(0.57)(sin 90^{\circ})}=0.089 T[/tex]
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