Answer:
See explanation below.
Explanation:
If the statement is a tautology is true for all the possible combinations and we can check this with the table of truth for the statements
Part a
[tex] (p \land q) \Rightarrow (p \lor r)[/tex] lets call this condition (1)
[tex] (p \land q)[/tex] condition (2) and [tex](p \lor r)[/tex] condition (3)
We can create a table like this one:
p q r (2) (3) (1)
T T T T T T
T T F T T T
T F T F T T
T F F F T T
F T T F T T
F T F F F T
F F T F T T
F F F F F T
So as we can see we have a tautology since for all the possibilites we got true the final result.
Part b
[tex] p \Rightarrow (r \Rightarrow p)[/tex] let's call this condition (1)
And let [tex] (r \Rightarrow p)[/tex] condition (2)
We can create the following table:
p r (2) (1)
T T T T
T F T T
F T F T
F F T T
So is also a tautology since the statement is true for all the possibilities or combinations.