Answer:
The magnitude of the average force exerted on the water by the blade is 960 N.
Explanation:
Given that,
The mass of water per second that strikes the blade is, [tex]\dfrac{m}{t}=30\ kg/s[/tex]
Initial speed of the oncoming stream, u = 16 m/s
Final speed of the outgoing water stream, v = -16 m/s
We need to find the magnitude of the average force exerted on the water by the blade. It can be calculated using second law of motion as :
[tex]F=\dfrac{\Delta P}{\Delta t}[/tex]
[tex]F=\dfrac{m(v-u)}{\Delta t}[/tex]
[tex]F=30\ kg/s\times (-16-16)\ m/s[/tex]
F = -960 N
So, the magnitude of the average force exerted on the water by the blade is 960 N. Hence, this is the required solution.
