Answer: Option (A) is the correct answer.
Explanation:
It is known that the relation between force and electric field is as follows.
F = qE .......... (1)
where, F = force
q = charge
E = electric field
Also, we know that, F = ma ...... (2)
Hence, equating equation (1) and (2) as follows.
qE = ma
or, q = [tex]\frac{ma}{E}[/tex]
Therefore, putting the given values into the above formula as follows.
q = [tex]\frac{ma}{E}[/tex]
= [tex]\frac{441 g \times 13.0 m/s^{2}}{5.0 N/C}[/tex]
= 1.1466 C
= 1.15 C (approx)
Therefore, we can conclude that the charge carried by given charge is 1.15 C.
