Answer:
a. 0.9263
b. 0.4872
c. 13.83kN/m[tex]^{3}[/tex]
Explanation:
moisture content (ω) = 0.32
void ratio (e) = 0.95
specific gravity ([tex]G_{s}[/tex]) = 2.75
the degree of satruation (S) = [tex]\frac{w . G_{s} }{e}[/tex] =0.32×2.75/0.95 = 0.9263
b. porosity (n) = [tex]\frac{e}{e + 1}[/tex] = 0.95/(0.95 + 1)= 0.4872
c. dry unit weight (γ[tex]_{d}[/tex]) = [tex]\frac{G_{s} . V_{w} }{1 + e}[/tex]
taking specific unit weight of water (V[tex]_{w}[/tex])= 9.81kN/m[tex]^{3}[/tex]
γ[tex]_{d}[/tex] = 2.75 × 1000/(1 + 0.95) = 13.83kN/m[tex]^{3}[/tex]
