Answer:
[tex] \Delta x = \frac{-60}{6}=-10[/tex]
So then the correct answer on this case would be:
D) decreases by 10.
Explanation:
For this case we assume that we have a linear model given by this expression:
[tex] y = mx+b[/tex]
Where m is the slope on this case m=6 and b the intercept.
So our model is given by: [tex] y = 6x +b[/tex]
We want to see that if we decrease the value of y on 60 units what would be the change on the x axis.
Let's assume that we have two points [tex] y_i = 6 x_i + b[/tex] and [tex] y_f = 6 x_f +b[/tex]
If we find the differences between those points we got:
[tex] y_f - y_i = 6x_f +b -6x_i -b = 6 (x_f -x_i)[/tex]
And we can rewrite this like that:
[tex] \Delta y = 6 \Delta x[/tex]
And if we know that [tex] Delta y =-60[/tex] then we can solve [tex] \Delta x[/tex] like this:
[tex] \Delta x = \frac{-60}{6}=-10[/tex]
So then the correct answer on this case would be:
D) decreases by 10.
