Answer:
8. The volume of the rocket is [tex]105\pi[/tex] [tex]inch^{3}[/tex].
9. Matt made the error by putting the value of the diameter.
Step-by-step explanation:
8. The volume of the rocket = the volume of the cone + the volume of the cylinder.
The volume of the cone is = [tex]\frac{1}{3} \pi \times radius^{2} (height) = \frac{1}{3} \pi \times 3^{2} \times5 = 15\pi[/tex] [tex]inch^{3}[/tex].
The volume of the cylinder is [tex]\pi \times radius^{2} \times height = \pi \times 3^{2} \times 10 = 90\pi[/tex] [tex]inch^{3}[/tex].
The total volume is [tex]15\pi + 90\pi = 105\pi inch^{3}[/tex].
9. Matt made the error in calculating the volume.
The diameter of the spherical ball is given by 15 centimeter.
The volume of a spherical ball is calculated by the formula [tex]\frac{4}{3} \pi \times radius^{3}[/tex].
Matt put the diameter of the spherical ball instead of its radius.
