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Under what conditions does an increase in temperature turn a nonspontaneous process into a spontaneous process?

Choose one or more:

a. ΔH < 0, ΔS > 0
b. ΔH > 0, ΔS > 0
c. ΔH > 0, ΔS < 0
d. ΔH < 0, ΔS < 0

(What I'm trying to figure out is if you need to consider T being negative OR positive to start)

Respuesta :

pstnonsonjoku

Answer:ΔH < 0, ΔS > 0

Explanation:

Consider ∆G= ∆H-T∆S

If ∆H is negative and and ∆S is positive, when T is increased, T∆S becomes more positive until the result of the difference between ∆H-T∆S becomes negative. Remember that a reaction is only spontaneous when ∆G is negative. Hence under these conditions, ∆G becomes negative and the reaction becomes spontaneous.

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