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A small block has constant acceleration as it slides down a frictionless incline. The block is released from rest at the top of the incline, and its speed after it has traveled 7.80 m to the bottom of the incline is 3.80 m/s .What is the speed of the block when it is 5.00 m from the top of the incline? Please show the detailed formulas utilized to obtain the final answere

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Answer:

The speed of the block when it is 5.00 m from the top of the incline is 3.04 m/s

Explanation:

given information:

s = 7.80 m

v = 3.8 m/s

if s = 5 m, v?

first we have to find the acceleration of the block using the following equation:

v² = v₀² + 2as, v₀²  = 0 thus

3.8² = 2 a 7.8

a = 0.93

so, if s = 5m the final speed is

v² = 2 (0.93) (5)

   = 9.26

v = √9.26

  = 3.04 m/s

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