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The 2-kg spool S fits loosely on the inclined rod for which the coefficient of static friction is μs=0.2. If the spool is located 0.25 m from A, determine the maximum constant speed the spool can have so that it does not slip up the rod

Respuesta :

Answer:

v = 0.969 m/s

Explanation:

See attachment for FBD

p = 0.25*(4/5) = 0.2 m

Sum of normal forces

Ns (3/5) - 0.2*Ns*(4/5) = 2 * (v^2 / 0.2)

Sum of vertical forces

Ns (4/5) - 0.2*Ns*(3/5) = 2*9.81

Solve both equations simultaneously to get Ns and v

Ns = 21.3 N

v = 0.969 m/s

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