x= 0 and x= 1
Step-by-step explanation:
Given g(x) = x+2 and f(x) = [tex]2^x+1[/tex]
If f(x) = g(x)
⇔[tex]2^x+1[/tex] = x+2
⇔[tex]2^x= x +1[/tex]
Only x= 1 and x=0 will be satisfy the above equation.
If x= 1, it gives and x=0 gives
[tex]2^1= 1+1[/tex] [tex]2^0=0+1[/tex]
⇔2=2 ⇔1=1
