Answer:
∴ ∠BAD = [tex]sin^{-1}[/tex](0.2044) = 11.8°
Step-by-step explanation:
i) AD = 9 cm
ii) DC = 3 cm
iii) ∠BCD = 35°
iv) Since AB is parallel to DC and ∠ABD = 90° then we can conclude that ∠BDC = 90°.
v) [tex]\frac{BD}{DC} = \frac{BD}{3\hspace{0.1cm}cm} = tan(35)[/tex] = 0.6128 ∴ BD = 3 [tex]\times[/tex] 0.6128 = 1.84 cm
vi) ∴ sin(∠ BAD ) = [tex]\frac{BD}{AD}[/tex] ⇒ sin(∠ BAD ) = [tex]\frac{1.84}{9}[/tex] = 0.2044
∴ ∠BAD = [tex]sin^{-1}[/tex](0.2044) = 11.8°
