Respuesta :
The given question is incomplete. The complete question is as follows.
Citrate synthase catalyzes the reaction
Oxaloacetate + acetyl-CoA [tex]\rightarrow[/tex] citrate + HS-CoA
The standard free energy change for the reaction is -31.5 kJ*mol^-1
( a) Calculate the equilibrium constant for this reaction a 37degrees C
Explanation:
(a). It is known that , relation between change in free energy ([tex]\Delta G[/tex]) of a reaction and equilibrium constant (K) is as follows.
[tex]\Delta G = -RT \times ln K[/tex]
where, T = temperature in Kelvin
The given data is as follows.
T = 310 K, [tex]\Delta G = -31.5 kJ /mol = -31500 J/mol[/tex] (as 1 kJ = 1000 J)
Now, putting the given values into the above formula as follows.
ln K = [tex]\frac{-(\Delta G)}{RT}[/tex]
= [tex]\frac{31500}{8.314 \times 310}[/tex]
ln K = 12.22
K = antilog (12.22)
= [tex]2.1 \times 10^{5}[/tex]
Therefore, we can conclude that value of equilibrium constant for the given reaction is [tex]2.1 \times 10^{5}[/tex].
