Answer: The mean of this binomial distribution is 53.36.
Step-by-step explanation:
We know that , the mean of this binomial distribution is given by :_
[tex]\mu = np[/tex]
, where n = sample size or the number of possible trials .
p = probability of getting success in each trial.
We are given that , the probability of success in each of the 58 identical engine tests is p = 0.92.
i.e. n= 58
p=0.92
Then, the mean of this binomial distribution = [tex]58\times0.92=53.36[/tex]
Hence , the mean of this binomial distribution is 53.36.
