Answer: The work energy lost by the system is -6078 Joules
Explanation:
According to first law of thermodynamics:
[tex]\Delta E=q+w[/tex]
[tex]\Delta E[/tex]=Change in internal energy
q = heat absorbed or released
w = work done or by the system
w = work done by the system=[tex]-P\Delta V[/tex] {Work is done by the system as the final volume is greater than initial volume and is negative}
where P = pressure = 3 atm
[tex]\Delta V[/tex] = change in volume = (55-35) L = 20 L
w =[tex]-3atm\times (20)L=-60Latm=-6078Joules[/tex]
{1Latm=101.3J}
Thus work energy lost by the system is -6078 Joules
