The average force is -2600 N
Explanation:
First of all, we need to calculate the acceleration of the man during the collision, which is given by the suvat equation:
[tex]v^2-u^2=2as[/tex]
where:
v = 0 is his final velocity (he comes to a stop)
u = 4.0 m/s is the initial velocity
a is the acceleration
s = 0.20 m is the distance covered
Solving for a,
[tex]a=\frac{v^2-u^2}{2s}=\frac{0-4.0^2}{2(0.20)}=-40 m/s^2[/tex]
The negative sign indicates that it is a deceleration.
Now we can find the average force on the man by using Newton's second law of motion:
[tex]F=ma[/tex]
where
m = 65 kg is the mass
[tex]a=-40 m/s^2[/tex]
And substituting,
[tex]F=(65)(-40)=-2600 N[/tex]
where the negative sign indicates the force is in the direction opposite to the motion.
Learn more about force and Newton's second law:
brainly.com/question/3820012
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