Answer:
0.9964 is the probability that at least one of them meets specifications.
Step-by-step explanation:
We are given the following in the question:
B: Bolts meet the specification
N: Nails meet the specification
P(B) = 96% = 0.96
P(N) = 91% = 0.91
One bolt and one nail are chosen independently.
Thus, we can write
[tex]P(B\cap N) = P(B) \times P(N) = 0.96\times 0.91 = 0.8736[/tex]
We have to find the probability that at least one of them meets specifications.
[tex]P(B\cup N) = P(B) + P(N) -P(B\cap N)\\P(B\cup N) =0.96 + 0.91-0.8736\\P(B\cup N) =0.9964[/tex]
0.9964 is the probability that at least one of them meets specifications.
