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in a class of 26 students, 15 of them like maths, 13 of them like english and 9 of them like neither. find the probability that a student chosen at random likes english but not maths.

venn diagram doesn't need to be completed,, some working out would help because this is exam revision. thanks!

in a class of 26 students 15 of them like maths 13 of them like english and 9 of them like neither find the probability that a student chosen at random likes en class=

Respuesta :

jimohfawwazajibola25

Answer:

0.0769

Step-by-step explanation:

Let x be the number of student that offer both subjects

15 - x + x + 13 - x + 9 = 26

-x + 37 = 26

-x = -11

x = 11

Number of student that offer english but not math = 13 - 11

                                                                                        = 2

The probability of english but not math = 2/26

aksnkj

The probability that a student is chosen at random likes English but not maths is [tex]\dfrac{1}{13}[/tex].

Given information:

In a class of 26 students, 15 of them like maths, 13 of them like English and 9 of them like neither.

Now, the number of students who like either maths or English will be,

[tex]26-9=17[/tex]

Now, out of 17, 15 students like maths and 13 students like English.

So, the number of students who like both the subjects will be,

[tex]E\cap M=13+15-17\\=11[/tex]

Now, 11 students like both the subjects and 13 students like English.

So, the number of students who like English but not maths will be,

[tex]13-11=2[/tex]

Thus, the probability that a student chosen at random likes English but not maths will be calculated as,

[tex]P=\dfrac{2}{26}\\=\dfrac{1}{13}[/tex]

Therefore, the probability that a student is chosen at random likes English but not maths is [tex]\dfrac{1}{13}[/tex].

For more details, refer to the link:

https://brainly.com/question/21586810