Answer:
The location will be at [tex]- 28\frac{1}{8}[/tex] units.
Step-by-step explanation:
A scuba diver descended at a rate of [tex]2\frac{1}{4}[/tex] units per second.
Now, if 0 represents the surface of the water and distances below the surface are negative, then after [tex]12\frac{1}{2}[/tex] seconds the location of the diver will be given by the followings :
In one second the diver descends by 2.25 units depth.
So, in 12.5 seconds the diver will descend by [tex](2.25 \times 12.5) = 28.125[/tex] units i.e. [tex]28\frac{1}{8}[/tex] units depth.
Therefore, the location will be at [tex]- 28\frac{1}{8}[/tex] units. (Answer)
