Answer:
392307.6923 m/s²
Explanation:
t = Time taken
u = Initial velocity = 560 m/s
v = Final velocity = 460 m/s
s = Displacement = 13 cm
a = Acceleration
From the equation of motion we have
[tex]v^2-u^2=2as\\\Rightarrow a=\dfrac{v^2-u^2}{2s}\\\Rightarrow a=\dfrac{460^2-560^2}{2\times 13\times 10^{-2}}\\\Rightarrow a=-392307.6923\ m/s^2[/tex]
The acceleration of the bullet as it passes through the board is -392307.6923 m/s²
