Answer:
There are [tex]2.12\times 10^{19}\ electrons[/tex] that must be removes from an electrically neutral silver dollar.
Explanation:
In this case, we need to find the number of electrons must be removes from an electrically neutral silver dollar to give it a charge of +3.4 C. Let n number of electrons removed. It is a case of quantization of electric charge. It is given by :
q = ne
[tex]n=\dfrac{q}{e}[/tex]
e is the charge on an electron
[tex]n=\dfrac{3.4\ C}{1.6\times 10^{-19}\ C}[/tex]
[tex]n=2.12\times 10^{19}\ electrons[/tex]
So, there are [tex]2.12\times 10^{19}\ electrons[/tex] that must be removes from an electrically neutral silver dollar.
