A 880 N crate rests on the floor. (a) How much work is required to move it at constant speed 4.8 m along the floor against a friction force of 180 N?

Respuesta :

Answer:

We have to do 864 J for moving the crate

Explanation:

We have given a 880 N crate is at rest on the floor

Frictional force f = 180 N

We have to move the crate by 4.8 m

For moving the crate we have to overcome the frictional force acting the crate

We know that work done is given by [tex]Work\ done=force\times distance[/tex]

Here force will be equal to frictional force and distance is 4.8 m

So work done [tex]W=180\times 4.8=864J[/tex]

So we have to do 864 J for moving the crate