In solving a two-order linear inequality, say
[tex]y>m_1 x[/tex] and [tex]y \ge m_2 x +c[/tex]
We graph the corresponding linear equations;
[tex]\left \{ {{y=m_1 x} \atop {y= m_2 x+c}} \right.[/tex]
Each of the two equations divides the cartesian plane into half-planes.
By testing for points, we identify the half-plane that satisfies each inequality.
The intersection of the two half-planes gives us a set of points that satisfies the two inequalities simultaneously.
Therefore the solution to the two-order inequality is the intersection of two half-planes.
The correct answer is option C
