A plastic sphere floats in water with 50.0% of its volume submerged. This same sphere floats in glycerin with 40.0% of its volume submerged. Determine the densities of:a. The glycerin b. The sphere.

Respuesta :

Explanation:

weight of water displaced=weight of sphere,

Since,  plastic sphere floats in water with 50.0% of its volume submerged

so, water=2 sphere,

so sphere's density = 1/2 of water's  density

Now,  weight of glycerin displaced=weight of sphere,

Also given This same sphere floats in glycerin with 40.0% of its volume submerged.

so glycerin =2.5 sphere,

so sphere's density = .4 of glycerin's = 1/2 of water's.

So glycerin = 1.25 water

Density of glycerin is  5/ 4 times of water density.

Density of sphere is 1/2 times of water density.

Density is defined as ratio of mass to volume , that is density is the amount of mass per unit of volume.

Since,  plastic sphere floats in water with 50% of its volume submerged.

So, Density of sphere = [tex]\frac{1}{2} *water density[/tex]

Since, same sphere floats in glycerin with 40% of its volume submerged.

So, Density of sphere = [tex]\frac{40}{100}*Glycerin density=\frac{2}{5}*glycerindensity[/tex]

Density of Glycerin =  5/2  of sphere density

Density of glycerin =  [tex]\frac{5}{2}*\frac{1}{2}*waterdensity[/tex]

Density of glycerin = [tex]\frac{5}{4} *waterdensity[/tex]

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