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A +6.00 μC point charge is moving at a constant 9.00 ×10^6m/s in the + y-direction, relative to a reference frame.
At the instant when the point charge is at the origin of this reference frame, what is the magnetic field B it produces at the following points?

A) x=0.500m,y=0, z=0
B) x=0, y=-0.500m, z=0
C) x=0, y=0, z=+0.500m
D) x=0, y=-0.500m, z=+0.500m

Respuesta :

SOLUTION OF EACH CASES ARE GIVEN BELOW.

Explanation:

We know magnetic field due to a charge q moving with a velocity v [tex]=\dfrac{\mu_oq}{4\pi r^3}(v \times r)[/tex].

Case A:

r=0.5i

Putting value of r, q and v .

We get, [tex]B=-2.34\times 10^{-5} \ k.[/tex] [tex](\ j\times i=-k)[/tex]

Case B:

r=0.5 j

B=0 [tex]( j\times j=0)[/tex]

Case C:

We get, [tex]B=2.34\times 10^{-5} \ i\ (Since\ , j \times k=i)[/tex]

Case D:

We get , [tex]B=8.28\times 10^{-6} \ T \ i[/tex].

Learn more:

Magnetism

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