What are the slope and the y-intercept of the linear function that is represented by the equation 8 x minus 2 y = 5?
The slope is Negative five-halves, and the y-intercept is 4.
The slope is Five-halves, and the y-intercept is 4.
The slope is 4, and the y-intercept is Negative five-halves.
The slope is 4, and the y-intercept is Five-halves.

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Answer:

The slope is 4, and the y-intercept is Negative five-halves

Step-by-step explanation:

we have

[tex]8x-2y=5[/tex]

This is the equation of the line in standard form

Convert the equation in slope intercept form

[tex]y=mx+b[/tex]

where

m is the slope

b is the y-intercept

Isolate the variable y

Subtract 8x both sides

[tex]-2y=-8x+5[/tex]

Divide by -2 both sides

[tex]y=4x-\frac{5}{2}[/tex]

therefore

[tex]m=4\\b=-\frac{5}{2}[/tex]

The slope is 4, and the y-intercept is Negative five-halves

Given that,

  • The linear function that is represented by the equation 8 x minus 2 y = 5.

Based on the above information, the calculation is as follows:

8x - 2y = 5

We know that y = mx + b

Here  

m is the slope

b is the y-intercept

Isolate the variable y

So,

-2y = -8x + 5

Now divide 2 by both sides

[tex]y = 4x - \frac{5}{2}[/tex]

So,

m = 4

And b [tex]= \frac{-5}{2}[/tex]

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