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Please help!
Find the solutions of each equation on the interval [0,2pi).
(SHOW WORK)
Picture below.

Please help Find the solutions of each equation on the interval 02pi SHOW WORK Picture below class=

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sqdancefan

Answer:

  x = 0

Step-by-step explanation:

The argument x+3π/2 shifts the sine function 3π/2 to the left, making it equivalent to -cos(x). Then the equation becomes ...

  -2cos(x) = -2

  cos(x) = 1

On the interval [0, 2π), cos(x) is only 1 at x=0.

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