The ratio (2nd to 1st) of their kinetic energies is 4
Explanation:
The kinetic energy of an object is the energy possessed by the object due to its motion, and it is calculated as
[tex]K=\frac{1}{2}mv^2[/tex]
where
m is the mass of the object
v is its speed
In this problem, we have:
- A first object with mass m and speed V, so its kinetic energy is
[tex]K_1 = \frac{1}{2}mV^2[/tex]
- A second object with mass m (same as first object) and speed 2V, so its kinetic energy is
[tex]K_2 = \frac{1}{2}m(2V)^2=4(\frac{1}{2}mV^2)[/tex]
So, the ratio of theri kinetic energies is
[tex]\frac{K_2}{K_1}=\frac{4(\frac{1}{2}mV^2)}{\frac{1}{2}mV^2}=4[/tex]
Learn more about kinetic energy:
brainly.com/question/6536722
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