Respuesta :
The equation of a parabola with a vertex at (h,k) is
f(x)=a(x-h)+k
where a is a constant not equal to zero.
So for (h,k)=(-2,0), the general equation is
y=f(x)=a(x--2)^2+0,
y=a(x+2)^2, or
If a=1 and expand,
y=x^2+4x+4
f(x)=a(x-h)+k
where a is a constant not equal to zero.
So for (h,k)=(-2,0), the general equation is
y=f(x)=a(x--2)^2+0,
y=a(x+2)^2, or
If a=1 and expand,
y=x^2+4x+4
Answer:
The required equation of the parabola : y = x² + 4 + 4x
Step-by-step explanation:
The vertex of the parabola is given to be : (-2 , 0)
The equation of a parabola with a vertex at (h , k) is : f(x) = a(x - h)² + k , where a is a constant not equal to zero.
Now, Vertex : ( h , k) = (-2 , 0)
So, h = -2 and k = 0
⇒ f(x) = a(x + 2)² + 0
⇒ y = a(x + 2)²
Take a = 1
⇒ y = x² + 4 + 4x
This is the required equation of the parabola.