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A car with a mass of 1,000 kg moving with an initial velocity of 8 m/s is brought to rest by colliding with a truck. The collisions takes place over a time span of 0.2 s.Calculate the force exerted on the car

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maggie3772

Answer:

-40,000 N

Explanation:

First, use the kinematics equation v(f) = v(i) + at.  Final velocity is 0, initial is 8, and time is 0.2 seconds.  Solving for a, you get -40 m/s^2.  Then, use Newton’s second law, F=ma, to find the force.  F = (1000)(-40) = -40,000 N.

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