Answer:
The answer is 1
Step-by-step explanation:
i) [tex]\dfrac{(5\frac{4}{45} -4 \frac{1}{6})\div5\frac{8}{15} }{(4\frac{2}{3} +0.75)\times3\frac{9}{13}}\times34\frac{2}{7} + \frac{0.3\div0.01}{70} + \frac{2}{7}[/tex]
ii)[tex]\dfrac{(\frac{229}{45} -\frac{25}{6})\div\frac{83}{15} }{(\frac{14}{3} +\frac{3}{4})\times\frac{48}{13}}\times\frac{240}{7} + \frac{30}{70} + \frac{2}{7}[/tex]
iii)[tex](\dfrac{(\frac{458}{90} -\frac{375}{90})\times\frac{15}{83} }{(\frac{56}{12} +\frac{9}{12})\times\frac{48}{13}}\times\frac{240}{7}) + \frac{30}{70} + \frac{2}{7}[/tex]
iv) [tex](\dfrac{(\frac{83}{90})\times\frac{15}{83} }{(\dfrac{65}{12} )\times\dfrac{48}{13}}\times\dfrac{240}{7}) + \dfrac{30}{70} + \dfrac{2}{7}[/tex]
v)[tex](\dfrac{(\frac{1}{6}) }{(5\times4)}\times\dfrac{240}{7}) + \dfrac{30}{70} + \dfrac{20}{70}[/tex]
vi)[tex](\dfrac{1}{(6\times5\times4)}\times\dfrac{240}{7}) + \dfrac{50}{70}[/tex]
vii)[tex](\dfrac{1}{120}\times\dfrac{240}{7}) + \dfrac{50}{70}[/tex]
viii)[tex](\dfrac{2}{7}) + \dfrac{50}{70}[/tex]
ix)[tex]\dfrac{20}{70} +\dfrac{50}{70}[/tex]
x)[tex]= \dfrac{70}{70} \hspace{0.2cm} = \hspace{0.2cm} 1[/tex]
